Thanks for your input!

Allen

SELECT (SUM(IF(vote = 1, 1,0)) – SUM(IF(vote = 0, 1,0))) AS consensus
FROM votes
GROUP BY person ORDER BY consensus DESC

You can just total up the monthly fee field using the MySQL aggregate function SUM. Here is an example of the usage assuming the monthly fee field is just called fee and your table is called members:

SELECT SUM(fee) as total_sum
FROM members;

Thanks Knix

$row['total']? where is this defined?

The echo statement should also include your count field. Add an alias to the count and use that in the echo:

$query2 = (”SELECT sem_id, count(*) as total FROM `attendees` GROUP BY sem_id”);

echo "sem_id: " . $row['sem_id'] . " total: " . $row['total'] . "<br />";

I would run the raw query directly in the MySQL command line first to see if it works. This way, you do not need to worry about PHP just yet. Your query looks good and should work.

$db = mysqli_connect( “localhost” , “tester”, “123456″ , “tester” )
or die (“not able to connect.”);

$query2 = (“SELECT sem_id, count(*) FROM `attendees` GROUP BY sem_id”);
$result2 = mysqli_query($db , $query2);

if ($row = mysqli_fetch_assoc($result2 ))

{

echo $row[sem_id];

};

It almost seems like the GROUP BY modifier was not in the query.

Can you please give me the schema of your table so I can duplicate it?

56
34
23
89
56
56
56
34
09
09

56
34
23
89
56
56
56
34
09
09

and you want to count how many of “09″ there are and how many of “56″ there are…